define binding energy and obtain an expressio for binding energy of a satellite revolving in a circular orbit around the earth
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Answer:
Binding Energy can be defined as the minimum energy required to be supplied to it order to free thesatellite from the gravitational influence of the planet. (i.e; in order to take the satellite from the orbitto as point if infinity.) Consider asatellite revolving around a planet with speed V at a distance r.speed V at a distance r.
KE=\dfrac{1}{2} m_sV^2KE=21msV2
P.E= \dfrac{GM_pm_s}{r}P.E=rGMpms
E=\dfrac{GM_pm_s}{r^2}E=r2GMpms=\dfrac{msV^2}{r}rmsV2\Rightarrow m_3V^2⇒m3V2=\dfrac{4M_pm_s}{r}r4Mpms
KE=\dfrac{1}{2}KE=21\dfrac{Gm_sM_p}{r}rGmsMpT.E=2r−GMpms
B.E+T.E=0B.E+T.E=0(at infinite TE=0TE=0)
B.E=\dfrac{GP_pm_s}{2r}=0B.E=2rGPpms=0
B.E=\dfrac{GM_pm_s}{2r}B.E=2rGMpms
Hence Binding energy of satellite G of man m_smsrevolving around a planet of man M_pMp in a radius r
is=\dfrac{GM_pm_s}{2r}=2rGMpms