Physics, asked by Rishidevkumar, 4 months ago

Define electric field intensity at a point and find its value at a point due to an electric dipole when point is axial or equiterial or any point.
send me pic ​

Answers

Answered by Sriramgangster
7

Answer:

\huge\bigstar\underbrace{\mathtt\red{A}  \mathtt\purple{N} \mathtt\green{S}\mathtt\blue{W} \mathtt\blue{E} \mathtt\orange{R}}\bigstar

Explanation:

\huge\sf{\pink{\fbox{\blue{\fbox{\purple{\fbox{\pink{Definition:}}}}}}}}

Electric field intensity is the strength of an electric field at any point. It is equal to the electric force per unit charge experienced by a test charge placed at that point.

\huge\sf{\pink{\fbox{\blue{\fbox{\purple{\fbox{\pink{Expression:}}}}}}}}

Electric field due to an electric dipole at a point on its axial line: AB is an electric dipole of two point charges −q and +q separated by small distance 2d. P is a point along the axial line of the dipole at a distance r from the midpoint O of the electric dipole.

Electric field due to an electric dipole at a point on its axial line: AB is an electric dipole of two point charges −q and +q separated by small distance 2d. P is a point along the axial line of the dipole at a distance r from the midpoint O of the electric dipole.The electric field at the point P due to +q placed at B is,

After this, you can refer the photo:

\huge\fcolorbox{red}{blue}{20Thanks=Follow}

\huge\fcolorbox{red}{blue}{Follow=20Thanks}

Attachments:
Answered by Anonymous
0

Answer:

hope it's help full for u

Attachments:
Similar questions