Question

Define electric field intensity. Write its SI unit. Write the magnitude and direction of electric field intensity due to an electric dipole of length 2a at the midpoint of line joining the two charges. ​

Answer 1

Questions :

★Define electric field intensity.

★Write its SI unit.

★Write the magnitude and direction of electric field intensity due to an electric dipole of length 2a at the midpoint of line joining the two charges.

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$\Large\bold{\underline{\underline{Answer:-}}}$

Electric Field Intensity :

The electric field intensity of any point is defined as the force experienced by unit positive charge placed at that point.

$\bf\bold{E=\frac{F}{q_0}}$

The SI unit of electric field intensity =$\bf\bold{NC^{-1}}$

$\bf\small\bold{\underline{\underline{Step-By-Step\:Explanation:-}}}$

Electric field at any equatorial point of a dipole is $\bf\bold{\vec{E}=\frac{1}{4\pi\:\varepsilon_0}\frac{\vec{p}}{(r^2+a^2)^\frac{3}{2}}}$

At the mid-point of the dipole, r=0 so $\bf\bold{\vec{E}=\frac{1}{4\pi\:\varepsilon_0}\frac{\vec{p}}{a^3}}$

Answer 2

Answer:

Electric Field Intensity (E ) :

It is defined at any point due to source charge as the force experienced per unit positive test charge placed at a point without disturbing the source charge.

$\mathsf{F = Lim ( q_0 {\rightarrow{ 0)}}{\dfrac{ F} {q_0}}}$

S. I. Unit :

Newton per Coulomb ( N/C ) and it is a vector quantity.

Electric Field Intensity due to an electric dipole of length 2a at the mid point of the line joining the two charges,

E = $\mathsf{\dfrac{-P}{4{\pi{\epsilon_0}* {( r^2 + a^2)}^2}}}$

The direction of E due to dipole at any point on equatorial line is // to dipole & opposite to the direction of dipole moment ( - ve to +ve).

If a <<< r,

Magnitude, | $\mathsf{E _{equatorial}}$ | = $\mathsf{\dfrac{| P |}{4{\pi{\epsilon_0}* {r}^3 }}}$

Direction :

From +ve charge to - ve charge.