Chemistry, asked by bangarojuskingbbc, 9 months ago

define EMF cell ? The SRPdefine of Mg and Cd electrode is -2.37v and -0.40v respectively calculate the EMF of the cell Mg/Mg^+2//cd^+2/cd

Answers

Answered by rishabhmsa
0

Answer:

electro-magnified cell

Explanation:

EMF: 1234567890

Answered by tushargupta0691
0

Concept:

The electric potential produced by an electrochemical cell or by changing the magnetic field is referred to as electromotive force. EMF is a shortened form for electromotive force.

Given:

SRP of Mg = -2.37 V

SRP of Cd = -0.40 V

Find:

Define the EMF cell and calculate the EMF of the cell Mg/Mg⁺²//Cd⁺²/Cd.

Solution:

The cell notation is given as:

                               Anode||Cathode

So, Mg|Mg⁺² occurs at the anode where its oxidation takes place.

Cd⁺²|Cd occurs at the cathode where its reduction takes place.

EMF of a cell can be calculated as:

EMF = Ecell = Cell potential = Ecathode - Eanode

= -2.37 V - (-0.40)

= -2.37 + 0.40

= -1.97 V

Hence, the EMF of the cell Mg/Mg⁺²//Cd⁺²/Cd is -1.97 V.

#SPJ2

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