Physics, asked by varunsrivastava, 1 year ago

define escape velocity obtain an expression for the escape of the worby from the surface of the earth

Answers

Answered by RJ12345
0
minimum velocity given to object so as to escape from gravitational feild.
Vc= √GM/R
F is gravitational constant 6.67*10^-11
M is mass of earth 6*10^23 kg
R is radius of earth 6.4*10^6 m
on substituting these values in above formula
Vc= 11.2Km/sec
Similar questions