Question

define horizontal range and derive its expression​

Answer 1

Answer:The horizontal range of a projectile is the distance along the horizontal plane it would travel, before reaching the same vertical position as it started from.

Explanation:Horizontal range = Horizontal component of velocity × time of flight

or,R=ucosθ×2usinθg

or,R=u2sin2θg

Maximum horizontal range: The horizontal range will be maximum when sin2θ is maximum.

i.e.,sin2θor,2θor,θ=1=sin90o=90o=45o

Answer 2

Answer:

A projectile is an object that is given an initial velocity, and is acted on by gravity. The horizontal range of a projectile is the distance along the horizontal plane it would travel, before reaching the same vertical position as it started from. The horizontal range depends on the initial velocity v0, the launch angle θ, and the acceleration due to gravity. The unit of horizontal range is meters (m).

R = horizontal range (m)

v0 = initial velocity (m/s)

g = acceleration due to gravity (9.80 m/s2)

θ = angle of the initial velocity from the horizontal plane (radians or degrees)