Question

Define magnification and derive the relation m=h\h​

Answer 1

Answer:

Magnification refers to an action of magnifying something. Furthermore, it refers to enlarging the apparent size and not the physical size. This enlargement is certainly quantifiable.Furthermore, how an object magnifies in relation to its actual size, is an important discussion under magnification. In this topic, we will discuss this concept and how it helps to magnify objects

Let Hi be the enthalpy of a system in the initial state and Hf be the enthalpy of a system in the final state. Let Ui and Vi be the internal energy and volume in the initial state and Uf and Vf be the internal energy and volume in a final state.Now, as we know that,H=U+PVTherefore,Hi=Ui+PVi.....(1)Hf=Uf+PVf.....(2)Subtracting equation (1) from (2), we haveHf−Hi=(Uf+PVf)−(Ui+PVf)⇒Hf−Hi=(Uf−Ui)+P(Vf−Vi)⇒ΔH=ΔU+PΔV.....(3)

Here, ΔU and PΔV are the change in internal energy and work energy respectively.

Here, ΔU and PΔV are the change in internal energy and work energy respectively.Hence equation (3) is the relationship between H and U.

I HOPE THAT WAS HELPFUL FOR YOU PLEASE FOLLOW ME AND MARK ME AS BRAINLIEST.... :-D :D

♥︎♡♡♥︎

Answer 2

The ability of a microscope to produce an image of an object at a scale bigger (or even smaller) than its real size is known as magnification.

Explanation:

• Magnification is beneficial only when it is feasible to perceive more details of an object in a picture than when looking at it with the naked eye.
• The magnification formula is the ratio of the image's height to the object's height.
• Furthermore, the letter '$m$' denotes the object's magnification. Furthermore, its formula is as follows: Magnification $(m)=\frac{h}{h'}$.
• Here, $h$ is the height of the object and $h'$ is the height of the object.

• Besides, it can also be related to the object distance and image distance. So, it can be written as: $m=-\frac{v}{u}$

• Here $u$ is the object distance and $u$ is the image distance.
• Most noteworthy, in this way the magnification expression will be:$m=\frac{h'}{h}=-\frac{v}{u}$