Question

Define mathematical expectation of a discrete and continuous random variable and hence show that E(aX+b) =a E(X) + b​

Answer 1

Answer:

n probability theory, the expected value of a random variable X, denoted \operatorname {E}(X) or \operatorname {E} [X], is a generalization of the weighted average, and is intuitively the arithmetic mean of a large number of independent realizations of X

Step-by-step explanation:

Answer 2

Verified Answer

n probability theory, the expected value of a random variable X , deholed \ operatoname {E} [X] or \ operatorname {E} [X] ,is a generation of the weighted average, and is intuitively the areithmetic mean of large number of independent realisation of X