Question

Define molality of solution what is the mass of naoh present in 250 ml of a 3 molar solution of naoh

Answer 1

Answer:

Let x be the mass of solution.

Mass of NaOH=  

100

x×20

​  

 

Molar mass of NaOH=40g

∴ Number of moles= (  

100

20x

​  

)/40=  

200

x

​  

 

Now mass of solvent in the solution= x−  

100

20x

​  

=  

100

80x

​  

 

∴ Molality=  

(80x/100)

x/200

​  

×1000=6.25M