define Newton's law of gravitation. define an expression for it
Answers
Step-by-step explanation:
force between two masses, and that's the gravitational force, is equal to the gravitational constant G times the mass of the first object times the mass of the second object divided by the distance between the two objects squared. So this is newtons law
F=GmMd2.
hope it helps u
There is a spherical ball whose diameter is 7 cm is melted and converted into a wire of diameter 10 mm .
ANS:-. For cylindrical wire,
d=0.2cm,r 2
0.2
=0.1cm
Let the length of wire be xcm
So, according to problem Volume of cylindrical wire Volume of sphere
=πr
2h= 34
πr 3
=0.1×0.1×x= 34
×3×3×3
x= 0.1×0.1×0.1
4×3×3×3
x=3600cm or 36cm..
so, X= length
therefore :-. length is 36 cm..
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B.) If this wire is wounded around a cylindrical vessel of diameter 5 cm and overlap it properly . What will be the height of vessel and how many rounds will come around the vessel .
Recall that a cuboid, whose length, breadth and height are all equal, is called a cube. If each edge of the cube is a, then the surface area of this cube would be
2(a × a + a × a + a × a)
i.e., 6a2
hence here we should take it as 6 ( 5 ) = 30 cm.
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If this cylindercal vessel is 1 cm thick inside . Then what will be the mass of this vessel if density of vessel is 8 kg/cm before wounding a wire and after wounding wire .
ANS:-. From the figure we can observed that 1round of wire will cover 3 mm height of cylinder.
Number of rounds = Diameter of wireHeight of cylinder
=0.312=40 rounds .
Length of wire required in 1 round = Circumference of base of cylinder
=2πr=2π5=10π
Length of wire in 40 rounds =40×10π
=7400×22=78800=1257.14 cm
=12.57 m
Radius of wire = 20.3=0.15 cm.
Volume of wire = Area of cross-section of wire x Length of wire
=π(0.15)2×1257.14
=88.898 cm3
Mass = Volume x Density
=88.898×8.88
=789.41 gm.
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