Question

define open circuit and close circuit and draw it's diagram​

Answer 1

Explanation:

a closed circuit has a complete path for current to flow, whereas an open circuit doesn't, which means that it's not functional. Open circuit: The key in an open circuit represented as () Closed circuit:The key in the closed circuit represented as (.)

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Answer 2

What is Open Circuit?

Open Circuit means that the circuit is open and it's not closed, in simple words the circuit isn't complete

So, the current can't flow

In simple term we say "It's Off"

We put not dot ( ) in open Circuit

What is Closed Circut?

Close Circut means that the circuit is closed, in simple words there is no space left and so the current can flow from here

In simple term we say "It's On"

We put dot in closed Circut ( . )

Diagram of Open Circuit :-

$\setlength{\unitlength}{1.5cm}\begin{picture}(0,0)\linethickness{0.4mm}\put(8,1){\line(1,0){0.5}}\put(10.4,1){\line(1,0){0.6}}\put(8.7,1){\line(1,0){1.2}}\put(8,1){\line(0,2){2}}\put(11,1){\line(0,3){2}}\put(8,3){\line(3,0){1.3}}\put(9.7,3){\line(3,0){1.3}}\put(8.5,0.7){\line(0,1){0.5}}\put(8.7,0.8){\line(0,1){0.3}}\put(9.7,1){\sf{\large{ \bigg(}}}\put(10.2,1){\sf{\large{ \bigg)}}}\put(9.5,3){\circle{0.4}}\put(9.4,2.9){\line(3,2){0.3}}\put(9.6,2.8){\line( - 2,3){0.2}}\put(8.1,1.1){\sf{ + }}\put(8.7,1.1){\sf{ \large{ - }}}\put(8.5,0.2){\sf{ \large{O{p}en circuit }}}\end{picture}$

Diagram of Closed Circut :-

$\setlength{\unitlength}{1.5cm}\begin{picture}(8,2)\linethickness{0.4mm}\put(8,1){\line(1,0){0.5}}\put(10.4,1){\line(1,0){0.6}}\put(8.7,1){\line(1,0){1.2}}\put(8,1){\line(0,2){2}}\put(11,1){\line(0,3){2}}\put(8,3){\line(3,0){1.3}}\put(9.7,3){\line(3,0){1.3}}\put(8.5,0.7){\line(0,1){0.5}}\put(8.7,0.8){\line(0,1){0.3}}\put(9.7,1){\sf{\large{ \bigg(}}}\put(10.2,1){\sf{\large{ \bigg)}}}\put(9.5,3){\circle{0.4}}\put(9.4,2.9){\line(3,2){0.3}}\put(9.6,2.8){\line( - 2,3){0.2}}\put(8.1,1.1){\sf{ + }}\put(8.7,1.1){\sf{ \large{ - }}}\put(10.18,1){\circle*{0.1}}\put(8.5,0.2){\sf{ \large{Closed circuit }}}\end{picture}$