Question

Define Raoult’s Law with its expressions.

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Answer 1

Answer:

p0-ps/po =xsolute

where po=relative lowering of vapour pressure of solvent

PS =relative lowering of vapour pressure of the solution

xsolute =mole fraction of solute in solution

Explanation:

the relative lowering of vapour pressure of an volatile solution containing non-volatile solute is equal to the mole fraction of the solute in the solution..... this is called roult's law.

Answer 2

Explanation:

Raoult’s law states that a solvent’s partial vapour pressure in a solution (or mixture) is equal or identical to the vapour pressure of the pure solvent multiplied by its mole fraction in the solution.

Mathematically, Raoult’s law equation is written

as ;

Psolution = Χsolvent × P0solvent

where;

p solution = vapour pressure of the solution

x solution = mole fraction of solvent

P0 solution = vapour pressure of pure solvent..

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