Question

Define resolving power of an astronomical refracting telescope and write expression for it in normal adjustment.Assume that light of wave length 6000Å is coming from a star, what is the limit of resolution of a telescope whose objective has a diameter of 2.54m?

Answer 1

Answer:

The answer is 2.88 x 10^-10 radians.

Explanation:

In an astronomical telescope the reciprocal of  the smallest angular separation between two point objects whose images can just be resolved by the telescope is known as the resolving power of the whose images can just be resolved by the telescope.

Expression Δ θ = 1.22λ/ a

Solution:

D or "a" = 100 inch = 2.54  m

Lambda =6000 angstrom= 6 x 10-10 m

Putting the formula:

Δ θ  = 1.22 λ/ a = 1.22 x 6 x 10^-10/2.54

Δ θ = 7.32 x 10^-10/2.54

Δ θ  = 2.88 x 10^-10 radians