Question

Define SI unit of force.A force of 2N acting on a body changes its velocity uniformly from 2m/s to 5m/s in 10sec. Calculate the mass of the body.​

Answer 1

Answer:

S.I unit of Force is Newton

Given, Force(F) = 2N

Initial velocity(u) = 2m/s

Final velocity(v) = 5m/s

Time taken(t) = 10secs

Acceleration(a) = (v-u) /t

=(5-2)/10

=3/10

=0.3 m/s^2

F=ma (m = mass, a = acceleration)

2 = 0.3m

m = 6.66kg

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Answer 2

Answer :

Given that a force of 2N acting on a body changes its velocity uniformly from 2m/s to 5m/s in 10 seconds.

We have to find mass of body.

Solution :

$\sf{We \: have}\begin{cases}\sf{Force \: acting = 2\: N}\\\sf{Initial \: velocity = 2\: m/s}\\\sf{Final \: velocity = 5 \: m/s}\\\sf{Time \: = 10\: s}\\\sf\blue{Mass \: of \: body = ?}\end{cases}$

At first to find acceleration we will use 1st equation of motion :

$\longmapsto\large\underline{\boxed{\sf\purple{v = u + at }}}\\\\ \sf{Substituting\: values, }\\\\ \longmapsto\sf 5 = 2 + a \times 10 \\\\ \longmapsto\sf 5 = 2 + 10a \\\\ \longmapsto\sf 5 - 2 = 10a \\\\ \longmapsto\sf 3 = 10a \\\\ \longmapsto\sf a = 3/10 \\\\ \longmapsto\underline{\underline{\sf\green{a = 0.3 \: ms^{-2} }}}$

$\rule{150}{2}$

Now we will use Newton's 2nd law :

$\longmapsto\large\underline{\boxed{\bold\blue{F = m \times a }}} \\\\ \sf{Substituting \: values,}\\\\ \longmapsto\sf 2 = m \times 0.3 \\\\ \longmapsto\sf 2 = 0.3m \\\\ \longmapsto\sf m = 2/0.3 \\\\ \longmapsto\underline{\underline{\sf\purple{m = 6.67 \: kg}}}$

$\therefore\underline{\boxed{\text{Mass of body = 6.67 kg }}}$