Define solubality product (ksp) and derive the relation between solubality & solublity Product for [zr3 (Po4) ∆]
Answers
Solution:- (D) S=(
6912
K
sp
)
1/7
Zr
3
(PO
4
)
4
(s)⇌3Zr
4+
(aq.)+4PO
4
3−
(aq.)
K
sp
=[Zr
4+
]
3
[PO
4
3−
]
4
=(3S)
3
.(4S)
4
=6912 S
7
∴S=(
6912
K
sp
)
1/7
Answered By
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