Question

define Terminal velocity.........​

Answer 1

When a solid sphere falls through a highly viscous liquid, it experiences three forces.

One is the gravitational force (i.e. weight of the body) which acts downwards, W = mg = Vσg

Where, V is volume of the object, and σ is the density of material of the object.

Another is buoyant force , which always act in upward direction, and equal to the weight of the volume displaced by the object.

Thus, FB = Vρg, where, ρ is the density of the liquid.

It also suffers an upward drag force due to viscosity of the liquid which increases while going down which is given by, F = 6πηrv, where, η is coefficient of viscosity, r radius of sphere, and v velocity at a given instant.

As it depends on the value of v, it increases as the sphere falls down. For a certain value of v the sum of drag force and buoyant force becomes equal to the weight. This is the case of equilibrium.

Vσg = Vρg + 6πηrvt

or 6πηrvt = Vg (σ - ρ)

This velocity vt is called terminal velocity.

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Answer 2

Explanation:

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