Define terminal velocity for a spherical body and derive its formula. Raindrop of radius r has a terminal
velocity of v if it splits into 1000 drops of equal size find the velocity of the smaller drop
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Answer:
ᴛʜᴇ ᴛᴇʀᴍɪɴᴀʟ ᴠᴇʟᴏᴄɪᴛʏ ᴀᴄǫᴜɪʀᴇᴅ ʙʏ ᴛʜᴇ ʙᴀʟʟ ᴏғ ʀᴀᴅɪᴜs ʀ ᴡʜᴇɴ ᴅʀᴏᴘᴘᴇᴅ ᴛʜʀᴏᴜɢʜ ᴀ ʟɪǫᴜɪᴅ ᴏғ ᴠɪsᴄᴏsɪᴛʏ η ᴀɴᴅ ᴅᴇɴsɪᴛʏ ρ ɪs, ᴠ=2ʀ2(ρᴏ−ρ)ɢ9η. ɴᴏᴛᴇ:ᴛᴇʀᴍɪɴᴀʟ ᴠᴇʟᴏᴄɪᴛʏ ɪs ᴅᴇғɪɴᴇᴅ ᴀs ᴛʜᴇ ᴍᴀxɪᴍᴜᴍ ᴠᴇʟᴏᴄɪᴛʏ ᴀᴛᴛᴀɪɴᴇᴅ ʙʏ ᴀ ʙᴏᴅʏ ᴀs ɪᴛ ғᴀʟʟs ᴛʜʀᴏᴜɢʜ ᴀ ғʟᴜɪᴅ. ... sɪɴᴄᴇ ᴛʜᴇ ɴᴇᴛ ғᴏʀᴄᴇ ᴏɴ ᴛʜᴇ ʙᴏᴅʏ ɪs ᴢᴇʀᴏ, ᴛʜᴇ ʙᴏᴅʏ ʜᴀs ᴢᴇʀᴏ ᴀᴄᴄᴇʟᴇʀᴀᴛɪᴏɴ.
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Answer:
The small drops will have a terminal velocity equal to 10 times the terminal velocity of the big drop.
Explanation:
please see the enclosed attachment for detailed explanation and step by step working.
Terminal velocity= √[ g / k A]
g = gravity
k = constant depending on drag , air density etc
A = surface area of the sphere.
The terminal velocity is inversely proportional to the square root of the surface area.
Attachments:
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