Physics, asked by sy748916, 2 months ago

Define terminal velocity for a spherical body and derive its formula. Raindrop of radius r has a terminal

velocity of v if it splits into 1000 drops of equal size find the velocity of the smaller drop​

Answers

Answered by rajni6944
6

Answer:

ᴛʜᴇ ᴛᴇʀᴍɪɴᴀʟ ᴠᴇʟᴏᴄɪᴛʏ ᴀᴄǫᴜɪʀᴇᴅ ʙʏ ᴛʜᴇ ʙᴀʟʟ ᴏғ ʀᴀᴅɪᴜs ʀ ᴡʜᴇɴ ᴅʀᴏᴘᴘᴇᴅ ᴛʜʀᴏᴜɢʜ ᴀ ʟɪǫᴜɪᴅ ᴏғ ᴠɪsᴄᴏsɪᴛʏ η ᴀɴᴅ ᴅᴇɴsɪᴛʏ ρ ɪs, ᴠ=2ʀ2(ρᴏ−ρ)ɢ9η. ɴᴏᴛᴇ:ᴛᴇʀᴍɪɴᴀʟ ᴠᴇʟᴏᴄɪᴛʏ ɪs ᴅᴇғɪɴᴇᴅ ᴀs ᴛʜᴇ ᴍᴀxɪᴍᴜᴍ ᴠᴇʟᴏᴄɪᴛʏ ᴀᴛᴛᴀɪɴᴇᴅ ʙʏ ᴀ ʙᴏᴅʏ ᴀs ɪᴛ ғᴀʟʟs ᴛʜʀᴏᴜɢʜ ᴀ ғʟᴜɪᴅ. ... sɪɴᴄᴇ ᴛʜᴇ ɴᴇᴛ ғᴏʀᴄᴇ ᴏɴ ᴛʜᴇ ʙᴏᴅʏ ɪs ᴢᴇʀᴏ, ᴛʜᴇ ʙᴏᴅʏ ʜᴀs ᴢᴇʀᴏ ᴀᴄᴄᴇʟᴇʀᴀᴛɪᴏɴ.

Answered by kvnmurty
0

Answer:

The small drops will have a terminal velocity equal to 10 times the terminal velocity of the big drop.

Explanation:

please see the enclosed attachment for detailed explanation and step by step working.

Terminal velocity= √[ g / k A]

g = gravity

k = constant depending on drag , air density etc

A = surface area of the sphere.

The terminal velocity is inversely proportional to the square root of the surface area.

Attachments:
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