Define the divisibility by 6,7,8 and 9 and also write any one examle of each
Answers
Step-by-step explanation:
A number is divisible by 6 if it is divisible by 2 and 3 both. example- 12 = 2×2×3 so, it is dividable by both 2 as well as 3 hence it is dividable by 6
To determine if a number is divisible by 7, take the last digit off the number, double it and subtract the doubled number from the remaining number. If the result is evenly divisible by 7 (e.g. 14, 7, 0, -7, etc.), then the number is divisible by seven. This may need to be repeated several times.
Example- Is 3101 evenly divisible by 7?
310 - take off the last digit of the number which was 1
-2 - double the removed digit and subtract it
308 - repeat the process by taking off the 8
-16 - and doubling it to get 16 which is subtracted
14 - the result is 14 which is a multiple of 7
If the last three digits of a number are dividable by 8 then the number is dividable by 8.
example-19640 hear, 640 is dividable by 8 so 19640 is also dividable by 8.
If the sum of all the digits is dividable by 9 then the number is dividable by 9.
example- 27 hear,2+7=9 so 9 is dividable by 9 then 27 is also dividable by 9.
Answer:
wow dia03 itna writing........