Question

Define the empirical formula of oxide of iron which has 48 oxygen by mass

Answer 1

Explanation:

It is given that a oxide of iron in its empirical formula has 48 grams of oxygen So it contains 48/32 => 1.5 moles of oxygen. Hence the empirical formula of this compound is FeO1.5 ×2 => Fe2 O3 if iron has an oxidation state of +3 in this compound . Hope it helps you.