Physics, asked by anasanu1617, 5 hours ago

define the expression for time of height range and maximum height of perfect?​

Answers

Answered by dt074136
0

Explanation:

The range of an object, given the initial launch angle and initial velocity is found with: R=v2isin2θig R = v i 2 sin ⁡ 2 θ i g . The maximum height of an object, given the initial launch angle and initial velocity is found with:h=v2isin2θi2g h = v i 2 sin 2 ⁡ θ i 2 g .

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