define the expression
![s = ut + \frac{1}{2} {at}^{2} s = ut + \frac{1}{2} {at}^{2}](https://tex.z-dn.net/?f=s+%3D+ut+%2B++%5Cfrac%7B1%7D%7B2%7D++%7Bat%7D%5E%7B2%7D+)
in Mathematical and in graphical
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Answer:
Velocity is defined as the rate of change of displacement. This is mathematically represented as:
Velocity=DisplacementTime
Rearranging, we get
Displacement=Velcoity×Time
If the velocity is not constant then in the above equation we can use average velocity in the place of velocity and rewrite the equation as follows:
Displacement=(InitialVelocity+FinalVelocity2)×Time
Substituting the above equations with the notations used in the derivation of the first equation of motion, we get
s=u+v2×t
From the first equation of motion, we know that v = u + at. Putting this value of v in the above equation, we get
s=u+(u+at))2×t
s=2u+at2×t
s=(2u2+at2)×t
s=(u+12at)×t
On further simplification, the equation becomes:
s=ut+12at2
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Answer:
Derivation of Second Equation of Motion by Graphical Method
From the graph above, we can say that
Distance travelled (s) = Area of figure OABC = Area of rectangle OADC + Area of triangle ABD
s=(½AB×BD)+(OA×OC)
Since BD = EA, the above equation becomes
s=(½AB×EA)+(u×t)
As EA = at, the equation becomes
s=½×at×t+ut
On further simplification, the equation becomes
s=ut+½at²
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