Define the set p12(n20), and show |p12(n20)| = |p8(n20)|.
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20C12 = 20!/12!(20-12)! = 20!/12!(8!) and
20C12 = 20!/12!(20-12)! = 20!/12!(8!) and20C8 = 20!/8!(20-8)! = 20!/8!(12!) = 20C12
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