Question

Define the term mole how many molecules of seo2 are present in 22 gram of seo2

Answer 1

1 mole = 6.023 x 10^23 molecules = 1 molecular mass

1 mole = wt/mol.wt

mol. wt of SeO2 = 79+32 = 111 g

no.of moles that 22 g of SeO2 = 22 / 111 = 0.1982 moles

therefore no. of molecules = 0.1982 x 6.023 x 10^23

= 1.194 x 10^23 molecules.