define the term uniform acceleration A bus decreases it's speed from 72 km/h To 54 km/h in 5 seconds. find acceleration of the bus? class 9th science
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U=72 km/hr=72*5/18 m/s=20 m/s
v=54 km/hr=54*5/18 m/s=15 m/s
a=d/dt(v)
=>a=15-20/10
=>a=-5/10
=>a=-0.5 m/s^2
therefore,negative acceleration i.e.,deceleration of the bus is 0.5 m/s^2
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Answered by
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U=72 km/hr=72*5/18 m/s=20 m/s
v=54 km/hr=54*5/18 m/s=15 m/s
a=d/dt(v)
=>a=15-20/10
=>a=-5/10
=>a=-0.5 m/s^2
therefore,negative acceleration i.e.,deceleration of the bus is 0.5 m/s^2
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hii
I have a question
one
what does mean v=54km/hr=54*5/18m/s =15m/s
what is mean by *
54*5
please answer
* Means Multiplication sign..
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