Physics, asked by Ranubhai, 1 year ago

define the time period of wave

Answers

Answered by Anonymous
10
Time period of an wave :
The time needed for one complete cycle of vibration to pass a given point is called time period of an wave.
Time period decreases if frequency of the wave increases.

Hope it is useful to you.
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Answered by KDPatak
15

Consider a wave having Amplitude (A), angular frequency \bold{(\omega)}

Making x = 0 and initial phase\bold{(\phi)} = 0.

Diagram

\setlength{\unitlength}{2cm}\begin{picture}(1,1)\linethickness{0.4mm}\put(-0.4,1){\bold{y(t)}}\put(0,1){\vector(0,-1){2}}\put(0,0){\vector(2,0){2.6}}\put(0,0){\vector(0,1){1.7}}\qbezier(0,0)(0.3,1.5)(0.8,0)\qbezier(0.8,0)(1.3,-1.5)(1.6,0)\qbezier(1.6,0)(1.9,1.5)(2.4,-0.3)\put(0,0.9){\vector(1,0){0.3}}\put(0,1.2){\vector(1,0){2}}\put(0.06,1.02){(t)} \put(1,1.3){(T+t)} \put(2.6,-0.2){Time}\end{picture}

∴ the equation for displacement at time (t) becomes,

 \bold{\tt y(t)=Asin(\omega t)}......equ(1)

The same displacement is obtained at time (T+t).

\bold{\mathff{y(T+t)=Asin \omega (T+t)}}

or, \bold{\mathff{y(T+t)=Asin(\omega T+\omega t)}}.....equ(2)

The displacement is same

⇒ Asin (\bold{\omega}t) = A sin(\bold{\omega}T+\bold{\omega}t)

or, sin(\bold{\omega}t) = sin(\bold{\omega}T+\bold{\omega}t)

\bold{\omega}T = 2π

\bold{\mathff{T=\dfrac{2 \pi}{\omega}}}

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