Question

Define Time of light, Manimum height,
and Horizontal range and
drive also​

Answer 1

Answer:

Explanation:

The average velocity of a projectile between the instant it crosses one third the maximum height. It is projected with u making an angle θ with the vertical.

There will be a pair of points for which vertical velocities at the same height are in opposite direction and therefore their average sum =0

It is the horizontal velocity which is uniform and hence v  

av  = u  

x  = ucosθ

For a general point:

Displacement in Y-direction:

y= usinθ×t−  2 gt  2

 

​  

 

Displacement in X-direction:

x=ucosθ×t

Now in order to calculate average velocity:

Average Velocity =   Totaltime  NetDisplacement

​  

Answer 2

Answer:

1. Time of light: the time required for light to travel from any specified heavenly body to the earth

or

Time of flight: it is the time for which projectiles was in the air.

2. Maximum height: max. height is basically the total vertical distance covered by the projectiles

3. horizontal range: it is defined as the horizontal displacement of a projectile when the displacement of the projectiles in the y- direction is 0