define value of P such that
PZ square - PZ+ 81 = 0 has equal roots.
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PZ IS WHAT NUMBER DERVIED P IS WHAT &Z IS WHAT
aditya027:
that's wrong
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For equal roots, we know D = 0
That means b^2 -4 ac = 0
Now,
(-P)^2 - 4*P*81 =0
P^2 - 324P =0
P(P-324)=0
Either P=0 or P-324 = 0
That means P=0,324
Value of P can't be zero because of quadratic equation definition. So, P will be 324.
which will give P= 324 ,as the answer.
That means b^2 -4 ac = 0
Now,
(-P)^2 - 4*P*81 =0
P^2 - 324P =0
P(P-324)=0
Either P=0 or P-324 = 0
That means P=0,324
Value of P can't be zero because of quadratic equation definition. So, P will be 324.
which will give P= 324 ,as the answer.
but in option that gives 54,52,53,51. is it answer there
How ??
Options are wrong..
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