Question

definite integral of sin square x with the limit 0 to pi by 2 ​

Answer 1

Answer:

sin²X=1-cos2X/2

=1/2(1-cos2X)

=1/2(x-sin2x/2)

1/2[{π/2-1/2}-{0-0}]

π/4-1/4

this is your answer

Answer 2

Step-by-step explanation:

sin²x=1-cos2x/2

1/2(x-sin2x)

1/2{π/2}-1/2{sin2×0}

π/4-0

π/4 is write answer