Definite integration of log(x+root of x^2+1)
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log(x+√(x²+1))= sinhx
then integration of sinhx = coshx +c
we know coshx = log(x+√(x²-1))
therefore
integration of log(x+√(x²+1)) = log(x+√(x²-1)) +c
then integration of sinhx = coshx +c
we know coshx = log(x+√(x²-1))
therefore
integration of log(x+√(x²+1)) = log(x+√(x²-1)) +c
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