Question

Degree centigrade for 50% dissociation of pcl5 needed pressure value is

Answer 1

pcl 5 dissociates into PCL 3

Kp = Ppcl3*Ppcl2/Ppcl5

=   (0.5/1.5)^2 P2/0.5/1.5P = 1/3P

  =1/3 p =1.8,

P= 5.4 atm