Question

Degree of hardness of a sample of water containing 6mg of mgso4

Answer 1

Solution :

1 mol MgSO4=1molCaco3

2 mol MgSO4=2molCaco3

i.e 2×100gCaCO3

∴

Hardness of water = 220 ppm

Answer 2

Hey dear,

● Degree of hardness of water -
Hardness is usually expressed in terms of the equivalent quantity of calcium carbonate (CaCO3) in milligrams per litre or parts per million.

● Answer-
5 ppm

● Explaination-
# Given-

# Solution-
We have given,
1 kg water => 6 mg MgSO4
10^6 g water => 6 g MgSO4

We know,
1 mol MgSO4 => 1 mol CaCO3
120 g MgSO4 => 100 g CaCO3
6 g MgSO4 => 5 g CaCO3

Hence,
10^6 g water => 5 g CaCO3

Therefore, 5 ppm CaC03

Degree of hardness of water is 5 ppm.

Hope it helps you...