degree of the polynomial 3xsq+5x+2 is
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Given polynomial is 3x
Given polynomial is 3x 2
Given polynomial is 3x 2 −5x−2.
Given polynomial is 3x 2 −5x−2.X=
Given polynomial is 3x 2 −5x−2.X= 6
Given polynomial is 3x 2 −5x−2.X= 6−(−5)±
Given polynomial is 3x 2 −5x−2.X= 6−(−5)± 25+24
Given polynomial is 3x 2 −5x−2.X= 6−(−5)± 25+24
Given polynomial is 3x 2 −5x−2.X= 6−(−5)± 25+24
Given polynomial is 3x 2 −5x−2.X= 6−(−5)± 25+24
Given polynomial is 3x 2 −5x−2.X= 6−(−5)± 25+24 =
Given polynomial is 3x 2 −5x−2.X= 6−(−5)± 25+24 = 6
Given polynomial is 3x 2 −5x−2.X= 6−(−5)± 25+24 = 65±7
Given polynomial is 3x 2 −5x−2.X= 6−(−5)± 25+24 = 65±7
Given polynomial is 3x 2 −5x−2.X= 6−(−5)± 25+24 = 65±7 =2 or
Given polynomial is 3x 2 −5x−2.X= 6−(−5)± 25+24 = 65±7 =2 or 3
Given polynomial is 3x 2 −5x−2.X= 6−(−5)± 25+24 = 65±7 =2 or 3−1
Given polynomial is 3x 2 −5x−2.X= 6−(−5)± 25+24 = 65±7 =2 or 3−1
Given polynomial is 3x 2 −5x−2.X= 6−(−5)± 25+24 = 65±7 =2 or 3−1
Given polynomial is 3x 2 −5x−2.X= 6−(−5)± 25+24 = 65±7 =2 or 3−1 If α and β are roots of the equation ax
Given polynomial is 3x 2 −5x−2.X= 6−(−5)± 25+24 = 65±7 =2 or 3−1 If α and β are roots of the equation ax 2
Given polynomial is 3x 2 −5x−2.X= 6−(−5)± 25+24 = 65±7 =2 or 3−1 If α and β are roots of the equation ax 2 +bx+c=0, then
Given polynomial is 3x 2 −5x−2.X= 6−(−5)± 25+24 = 65±7 =2 or 3−1 If α and β are roots of the equation ax 2 +bx+c=0, thenax
Given polynomial is 3x 2 −5x−2.X= 6−(−5)± 25+24 = 65±7 =2 or 3−1 If α and β are roots of the equation ax 2 +bx+c=0, thenax 2
Given polynomial is 3x 2 −5x−2.X= 6−(−5)± 25+24 = 65±7 =2 or 3−1 If α and β are roots of the equation ax 2 +bx+c=0, thenax 2 +bx+c=a(X−α)(X−β)
Given polynomial is 3x 2 −5x−2.X= 6−(−5)± 25+24 = 65±7 =2 or 3−1 If α and β are roots of the equation ax 2 +bx+c=0, thenax 2 +bx+c=a(X−α)(X−β)Hence, 3x
Given polynomial is 3x 2 −5x−2.X= 6−(−5)± 25+24 = 65±7 =2 or 3−1 If α and β are roots of the equation ax 2 +bx+c=0, thenax 2 +bx+c=a(X−α)(X−β)Hence, 3x 2
Given polynomial is 3x 2 −5x−2.X= 6−(−5)± 25+24 = 65±7 =2 or 3−1 If α and β are roots of the equation ax 2 +bx+c=0, thenax 2 +bx+c=a(X−α)(X−β)Hence, 3x 2 −5x−2=3(X−2)(X+
Given polynomial is 3x 2 −5x−2.X= 6−(−5)± 25+24 = 65±7 =2 or 3−1 If α and β are roots of the equation ax 2 +bx+c=0, thenax 2 +bx+c=a(X−α)(X−β)Hence, 3x 2 −5x−2=3(X−2)(X+ 3
Given polynomial is 3x 2 −5x−2.X= 6−(−5)± 25+24 = 65±7 =2 or 3−1 If α and β are roots of the equation ax 2 +bx+c=0, thenax 2 +bx+c=a(X−α)(X−β)Hence, 3x 2 −5x−2=3(X−2)(X+ 31
Given polynomial is 3x 2 −5x−2.X= 6−(−5)± 25+24 = 65±7 =2 or 3−1 If α and β are roots of the equation ax 2 +bx+c=0, thenax 2 +bx+c=a(X−α)(X−β)Hence, 3x 2 −5x−2=3(X−2)(X+ 31
Given polynomial is 3x 2 −5x−2.X= 6−(−5)± 25+24 = 65±7 =2 or 3−1 If α and β are roots of the equation ax 2 +bx+c=0, thenax 2 +bx+c=a(X−α)(X−β)Hence, 3x 2 −5x−2=3(X−2)(X+ 31 )