degree of the polynomial 3xsq+5x+2 is
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Given polynomial is 3x2−5x−2.
X=6−(−5)±25+24
=65±7=2 or 3−1
If α and β are roots of the equation ax2+bx+c=0, then
ax2+bx+c=a(X−α)(X−β)
Hence, 3x2−5x−2=3(X−2)(X+31)
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