Question

Dehalogenation of 1,1,2,2 tetrachloroethane in alc. KOH and NaNH2 forms​

Answer 1

Answer:

Ethene

Explanation:

$\\\tt (Cl)_{2}CH-HC(Cl)_{2} -KOH \rightarrow (Cl)HC=CH(Cl)\\\\ \\\tt (Cl)HC=CH(Cl) -NNO_{2} \rightarrow ethene$

Answer 2

Ethyne is formed by dehalogenation of 1,1,2,2-tetrachloroethane.

Explanation:

• In the delaogenation reactions of di and tetra halide compounds there is removal of halogen atoms taking place from the compounds.
• A vicinal dihalides directly form alkynes, whereas geminal dihalides first form an alkenyl halide, then forms an alkyne.
• The tetrahalides also form alkynes.
• In the given reaction the dehalogenation of tetrahalide is taking place is presence of alcoholic potassium hydroxide and sodium amide to form an alkyne, the alkyne formed is ethyne.