Question

Del h &del sfor a reaction are and at 1atm pressure. The temperature at which free energy is equal to zero and the nature of the reaction below this temperature are :

Answer 1

H=+30.558KJ/mol

ΔS=0.066KJ/mol

P=1atm

ΔG=ΔH−TΔS

O=30.558−0.066×T

∴T=

0.066

30.558

∴T=463K⇒△G=0

As temperature decreases, the TΔS term decreases and as ΔH is positive, the ΔG terms becomes greater than zero which means that reaction becomes non-spntaneous.