Delsey and lcm of two number is 14 times their hcf the sum of their hcf and lcm is 600 if one number is 288 find the other number
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Step-by-step explanation:
80
the one number is 280 not 288
given lcm is 14 times hcf
let lcm = x
let hcf = y
x=14y ----------------(1)
given x + y= 600
14y + y = 600 (from 1)
15y = 600
y=600/15
y=40
substitute it in equation (1)
x=14y
x = 14*40
x = 560
therefor the LCM of two numbers is 560 and their HCF is 40
LCM*HCF=product of numbers
let the unknown number be (a)
560*40=280*a
a=560*40/280
a = 80
therefore the unknown number is 80
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