Question

Delta G. of reversible reaction at its equilibrium is

Answer 1

$\Delta G$ of reversible reaction at its equilibrium is zero.

Explanation:

Relation between standard Gibbs free energy and equilibrium constant follows:

$\Delta G=\Delta G^o+RT\ln K$

where,

$\Delta G^o$ = Standard Gibbs free energy

R = Gas constant

T = temperature

Putting values in above equation, we get:

$\Delta G=0$   at equilibrium

$\Delta G$ of reversible reaction at its equilibrium is zero.

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Answer 2

Answer:

0

Explanation:

The change in Gibbs free energy associated with a chemical reaction is a useful indicator of whether the reaction will proceed spontaneously.

Since the change in free energy is equal to the maximum useful work which can be accomplished by the reaction which is maximum at equilibrium.

Hence, △G = 0 at equilibrium