Question

DEMONSTRATION:

1. In figure 1a, AD = 8cm, CD = a = 8cm

2. In figure 1b, RQ = QP = b = 2 cm

3. In figure 2, AR = AB – RB = (a – b) = 8 – 2 = 6cm

4. In figure 4, since the square of 2 cm edge is taken out whose area is b2

= 22

, hence the net area of

ADCPQR = are of the square of 8 cm edge – area of the square of 2 cm edge = a2

– b

2

= 8

2

– 2

2 = 60 cm2

5. Refer to figure 4, since a 2 cm edge is taken out, hence AG = b = 2 cm

6. Therefore, GD = AD – AG = a – b = 8 – 2 = 6 cm

7. In figure 5, DR = DC + QR = a + b = 8 + 2 = 10 cm

8. Hence, area of the rectangle DRAG = DR GD = (a + b)(a – b) = (10)(6) = 60 cm2​

Answer 1

Answer:

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Step-by-step explanation: