Math, asked by ruthviksaikudupudi, 2 months ago

demovires theorm long answers type questions​

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Answered by nehabhosale454
62

Answer:

In mathematics, de Moivre's formula (also known as de Moivre's theorem and de Moivre's identity) states that for any real number x and integer n it holds that

{\displaystyle {\big (}\cos(x)+i\sin(x){\big )}^{n}=\cos(nx)+i\sin(nx),}{\displaystyle {\big (}\cos(x)+i\sin(x){\big )}^{n}=\cos(nx)+i\sin(nx),}

where i is the imaginary unit (i2 = −1). The formula is named after Abraham de Moivre, although he never stated it in his works.[1] The expression cos(x) + i sin(x) is sometimes abbreviated to cis(x).

The formula is important because it connects complex numbers and trigonometry. By expanding the left hand side and then comparing the real and imaginary parts under the assumption that x is real, it is possible to derive useful expressions for cos(nx) and sin(nx) in terms of cos(x) and sin(x).

As written, the formula is not valid for non-integer powers n. However, there are generalizations of this formula valid for other exponents. These can be used to give explicit expressions for the nth roots of unity, that is, complex numbers z such that zn = 1.

Step-by-step explanation:

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Answered by Uniquedosti00017
0

Answer:

see the attachment I have put challenging questions of demoivre's theorems.

if ur concept is good then u can solve them easily.

some important formula needed to solve these questions.

  • cosß + isinß = e^iß
  • cosß - isinß = e^-iß.

(a +b)² = a² + b² +2ab

(a - b)² = a² + b² -2ab

* if a + b + c = 0 then,

a³ + b³ +c³ -3abc = 0

* (a + b+ c)² = a² + b² + c² +2ab + 2bc + 2ca

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