Deniminator of a no. is less than its numerator by 4. If 6 is added to the numerator it becomes thrice of the denominator. Find the fraction...
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Here is the solution,
Let the Numerator be N, and Denominator be D,
According to the Question, The denominator is less than Numerator by 4,
=> D = N-4,
And Again according to the Question, If 6 is added to the numerator, It becomes thrice of Denominator,
=> (N+6) = 3D,
Substitute the above value of D here,
=> (N+6) = 3(N-4),
=> (N+6) = 3N - 12,
=> 18 = 2N,
=> N = 9,
Now substitute this in any of the above equations to get D,
=> D = 9-4,
=> D = 5,
We assumed the fraction as N/D,
Now the fraction is 9/5,
So therefore the answer to your question is 9/5,
Hope you understand, Have a great day !,
Thanking you, Bunti 360 !
Let the Numerator be N, and Denominator be D,
According to the Question, The denominator is less than Numerator by 4,
=> D = N-4,
And Again according to the Question, If 6 is added to the numerator, It becomes thrice of Denominator,
=> (N+6) = 3D,
Substitute the above value of D here,
=> (N+6) = 3(N-4),
=> (N+6) = 3N - 12,
=> 18 = 2N,
=> N = 9,
Now substitute this in any of the above equations to get D,
=> D = 9-4,
=> D = 5,
We assumed the fraction as N/D,
Now the fraction is 9/5,
So therefore the answer to your question is 9/5,
Hope you understand, Have a great day !,
Thanking you, Bunti 360 !
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