Question

Denominater of a fraction is
1 less than the three times.
of a numerater. If 13
is added to the denominator
then the fraction becomes
1. Find the original fraction

please help me to find this answer step by step​

Answer 1

Answer:

The original fraction is 4/11

Step-by-step explanation:

We know nothing about the numerator, so

THAT is where we assign the variable.

 

Let N be the numerator of the fraction.

Then the denominator is 3N-1 <--- it is 1 less than 3 times the numerator.

 

So the fraction looks like this:

 

      N

-------------

  3N - 1

 

 

Now what happens next is if both the numerator and the denominator

are increased by 3, the fraction becomes 1/2

 

so the fraction becomes:

 

 

     N+3                1

------------   =    -------  

 3N - 1+3             2

 

The denominator can be simplified:

 

 N+3             1

--------  =   ----------

3N + 2          2

 

Cross multiplication :

 

2(N+3) = 1*(3N+2)

 

2N + 6 = 3N + 2  <---- distributive property

 

0 = 3N + 2 - 2N - 6 <---- moves everything to the right side

 

0 = N - 4  <--- combines like terms

 

N = 4 <--- solves for N

 

So the numerator is 4

Then the denominator is 3*4 - 1 = 11

 

So the original fraction is 4/11

 

When 3 is added to both the numerator and denominator,

the fraction becomes 7/14 which does reduce to 1/2.

 

The original fraction is 4/11

Answer 2

Answer:Primary School Math 5+3 pts

Denominater of a fraction is

1 less than the three times.

of a numerater. If 13

is added to the denominator

then the fraction becomes

1. Find the original fraction

please help me to find this answer step by step​

by Pranitapatil0702 3 minutes ago

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umangsehrawat

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sanketsarve

SanketsarveExpert

Answer:

The original fraction is 4/11

Step-by-step explanation:

We know nothing about the numerator, so

THAT is where we assign the variable.

Let N be the numerator of the fraction.

Then the denominator is 3N-1 <--- it is 1 less than 3 times the numerator.

So the fraction looks like this:

N

-------------

3N - 1

Now what happens next is if both the numerator and the denominator

are increased by 3, the fraction becomes 1/2

so the fraction becomes:

N+3 1

------------ = -------

3N - 1+3 2

The denominator can be simplified:

N+3 1

-------- = ----------

3N + 2 2

Cross multiplication :

2(N+3) = 1*(3N+2)

2N + 6 = 3N + 2 <---- distributive property

0 = 3N + 2 - 2N - 6 <---- moves everything to the right side

0 = N - 4 <--- combines like terms

N = 4 <--- solves for N

So the numerator is 4

Then the denominator is 3*4 - 1 = 11

So the original fraction is 4/11

When 3 is added to both the numerator and denominator,

the fraction becomes 7/14 which does reduce to 1/2.

The original fraction is 4/11

Step-by-step explanation: