Question

Denominator after rationalizing 7/(5√3-5√2)

Answer 1

Answer:

25

Step-by-step explanation:

7/(5√3-5√2)

= 7/(5√3-5√2) * (5√3-5√2)/ (5√3-5√2)

=7(5√3+5√2)/(5√3)²-(5√2)²

=35√3+35√2 /75-50

= 35√3+35√2 /25

thus the denominator of 7/(5√3-5√2) is 25....

may be this answer was correct...

Answer 2

Denominator of 7/(5√3-5√2) after rationalizing is 5

Given : 7/(5√3-5√2)

To find : The denominator after rationalizing

Solution :

Step 1 of 2 :

Write down the given fraction

The given fraction is

$\displaystyle \sf{ \frac{7}{5 \sqrt{3} - 5 \sqrt{2} } }$

Step 2 of 2 :

Rationalize the denominator

$\displaystyle \sf{ \frac{7}{5 \sqrt{3} - 5 \sqrt{2} } }$

$\displaystyle \sf{ = \frac{7( \sqrt{3} + \sqrt{2} )}{5( \sqrt{3} - \sqrt{2})( \sqrt{3} + \sqrt{2} ) } }$

$\displaystyle \sf{ = \frac{7( \sqrt{3} + \sqrt{2} )}{5(3 - 2) } }$

$\displaystyle \sf{ = \frac{7( \sqrt{3} + \sqrt{2} )}{5 \times 1 } }$

$\displaystyle \sf{ = \frac{7( \sqrt{3} + \sqrt{2} )}{5 } }$

Denominator after rationalizing = 5

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