Question

denominator. Find the fraction,
5.Two years ago, a man was five times as old as his son. Two years later,
his age will be 8 more than three times the age of the son. Find the present
ages of the man and his son.​

Answer 1

Step-by-step explanation:

let the age of his son to be x - 2

and his father ( man ) to be 5x -2

ATQ,

5x - 2 + 2 = 3x + 8

5x - 3x = 8

2x = 8

X = 8/2 = 4

Present age of his son = 4 years

Present age of his father ( man ) = 5 × 4 = 20 years

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