denominator of a fraction is 1 less than the three times of numerator . If 13 is added to the numerator and 8 is added to the denominator then the fraction becomes 1, find the original number.
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Let the numerator be x
So the denominator will be one less than three times of numerator
x/3x-1
And now 13 is add to the numerator
8 add to the denominator
Then fraction becomes one
x+13/3x-1+8=1/1
Now cross multiplying
thus=x+13/3x+7=13/10
=13/10
Answer to this questions=13/10
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