Question

denominator of a fraction is greater than the numerator by 8 if numerator is increased by 17 and denominator is decreased by 1 the numerator obtained is 3 upon 2 find the fraction

Answer 1

Let the numerator be: x
Let the denominator be: x+8
So, the fraction will be: x/(x+8)

When the numerator is increased by 17 and denominator is decreased by 1, the fraction will be: (x+17)/(x+8-1)=(x+17)/(x+7)
which is equal to,
(x+17)/(x+7)=3/2
=>2x+34=3x+21
=>x=13

Therefore the fraction will be=13/21