Question

Densify of 2.03 m aqueous solution of acetic acid is is 1.017 gm/lmolecular mass of acetic acid is 60 calculate tha molality

Answer 1

Molality = 1000M/(1000D-M.Mwt) m = 1000*2.03/(1000*1.017–60*2.03) m = 2030/ 895.2 m = 2.268 The required molality is 2.268 molal.

Answer 2

Explanation:

density of 100 metre of aqua solution of Acetic Acid and 11 2017 and Molecular mass of Acetic acid is 60