Question

densities of a liquid at 30degree celsius and 80 degree celsius are 0.6gm/cc and 0.54gm/cc.The coefficient of real expansion of liquid is

Answer 1

Answer:

when you will start heating water it's temperature will rise gradually, and it's volume will start decreasing till 4°C and at this temperature density of water will be maximum. After that on further increasing the temperature again volume starts increasing and density starts decreasing.

Answer 2

Given:

Density of a liquid at 30°C is 0.6 g/cc , at 80°C is 0.54 g/cc.

To find:

Coefficient of real expansion of liquid.

Calculation:

Let density at 0°C be $\rho$ and coefficient of real expansion and be $\gamma$.

At 30°C :

$\therefore \: \rho1 = \rho(1 - \gamma \Delta \theta)$

$= > \: 0.60= \rho \{1 - ( \gamma \times 30) \}$

At 80°C :

$\therefore \: \rho2 = \rho(1 - \gamma \Delta \theta)$

$= > \: 0.54= \rho \{1 - ( \gamma \times 80) \}$

Dividing the two equations :

$= > \dfrac{0.60}{0.54} = \dfrac{1 - 30 \gamma }{1 - 80 \gamma }$

$= > \dfrac{10}{9} = \dfrac{1 - 30 \gamma }{1 - 80 \gamma }$

$= > 10 - 800 \gamma = 9 - 270 \gamma$

$= > 530 \gamma = 1$

$= > \gamma = \dfrac{1}{530}$

$= > \gamma = 1.88 \times {10}^{ - 3} \: \degree {c}^{ - 1}$

So , final answer is :

$\boxed{ \bold{ \green{ \gamma = 1.88 \times {10}^{ - 3} \: \degree {c}^{ - 1} }}}$