Question

Density for 2 M CH3COOH solution is(1.2g/ml) then calculate it's molality

Answer 1

Answer:

Suppose the volume of solution is 1000 ml

1 ml=1.2 gm

1000 ml=1020 gm

Number ofr moles =2⋅05M×1 lit=2.05 mol

Mass of solute =n×M⋅wt=2.05×60=123 gm

Solvent mass =1020−123=897 gm

Molality = 123/60× 1000/897

=2.28 mol kg^-1

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Answer 2

Answer:

mass of CH3COOH = 12+3+12+16+16+1 =60 gram

molality is 1.85m