Question

density of 1M solution of a non electrolyte C6H12O6 is 1.18g/ml. if Kf= 1.86 K Kg/MOL, solutuon freezes at...?

Answer 1

Answer:

Explanation:

Given:

 

Density = 2 g/mL.

 

Kf = 1.86°C kg/mol

Molarity = 1M

 

Molecular weight =100

 

freezing point =?

 

 

 

Volume space of space solution space equals space 1000 ml

Mass space of space solution space equals space Volume space cross times space Density

space space space space space space space space space space space space space space space space space space space space space space space space space space equals 1000 cross times space 2

Mass space of space solution space equals space 2000 space straight g

Amount space of space solute space in space 1000 space ml space of space solution space equals space 1 cross times space Molecular space weight

space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals space 100 space straight g

Mass space of space water space equals Mass space of space solution minus space Mass space of space solute

space space space space space space space space space space space space space space space space space space space space space space equals space 2000 minus 100

Mass space of space water space equals 1900 space gm

Molality space equals fraction numerator No. space of space moles space of space solute over denominator Weight space of space solvent space in space Kg end fraction

space space space space space space space space space space space space equals fraction numerator 1 over denominator begin display style bevelled 1900 over 1000 end style end fraction

Molality equals 0.5263 space straight m

We space know comma

increment straight T subscript straight f space equals space straight K subscript straight f times straight m

space space space space space space space equals space 1.86 cross times 0.5263

increment straight T subscript straight f space space equals space 0.9789 space to the power of ring operator straight C

increment straight T subscript straight f space equals straight T to the power of 0 subscript straight f minus straight T subscript straight f

straight T subscript straight f space equals space straight T to the power of 0 subscript straight f minus increment straight T subscript straight f space

space space space space equals 0 minus space 0.9789

straight T subscript straight f space space equals negative space 0.9789 space to the power of ring operator straight C

space space space space space equals negative space 0.9789 plus 273

space space space straight T subscript straight f equals space 272.02 space straight K

Answer 2

Explanation:

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