Question

density of 2.05M solution of acetic acid in water is 1.02g/ml.The molality of the solution

Answer 1

Explanation:

2.05/molecular massx1000/2.05/1.02 solve this problem u get urs answer perfectly

Answer 2

Answer:

Suppose the volume of solution is 1000 ml

1 ml=1.2 gm

1000 ml=1020 gm

Number of moles =2⋅05M×1 lit=2.05mol

Mass of solute =n×M⋅wt=2.05×60=123gm Solvent mass =1020−123=897 gm

Molality = 123/60 × 1000/897 =2.28 mol kg−1

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